A) \[\frac{l{{I}^{2}}}{2\pi }\]
B) \[\frac{l{{I}^{2}}}{4\pi }\]
C) \[\frac{{{l}^{2}}I}{2\pi }\]
D) \[\frac{{{l}^{2}}I}{4\pi }\]
Correct Answer: B
Solution :
If the radius of circle is r, then \[2\pi r=l\] Area \[=\pi {{r}^{2}}=\frac{{{l}^{2}}}{4\pi }\] Magnetic moment \[=IA=\frac{I{{l}^{2}}}{4\pi }\]
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