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BCECE Medical BCECE Medical Solved Papers-2008

  • question_answer
    1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

    A)  1.52

    B)  0.995

    C)  190

    D)  9

    Correct Answer: D

    Solution :

    \[\frac{{{E}_{Hydroxide}}}{{{E}_{metal}}+{{E}_{O{{H}^{-}}}}}>\frac{{{E}_{oxide}}}{{{E}_{metal}}+{{E}_{O}}}\]                 \[\frac{1.520}{E+17}=\frac{0.995}{E+8}\]  or \[E=9\]


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