A) \[C{{H}_{3}}\underline{C}OOH\]
B) \[C{{H}_{3}}\underline{C}ON{{H}_{2}}\]
C) \[C{{H}_{3}}\underline{C}{{H}_{2}}OH\]
D) \[C{{H}_{3}}\underline{C}{{H}_{2}}=C{{H}_{2}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{s{{p}^{2}}}{\mathop{C}}\,}}\,-OH\] \[C{{H}_{3}}\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{s{{p}^{2}}}{\mathop{C}}\,}}\,-N{{H}_{2}}\] \[C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,\underset{s{{p}^{3}}}{\mathop{-}}\,OH\] \[C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{s{{p}^{2}}}{\mathop{C}}\,}}\,=C{{H}_{2}}\]
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