A) \[BeC{{l}_{2}},\,s{{p}^{2}}\], linear
B) \[BeC{{l}_{2}},\,s{{p}^{2}}\], triangular planar
C) \[BeC{{l}_{3}},\,s{{p}^{2}}\], triangular planar
D) \[BeC{{l}_{3}},\,s{{p}^{2}}\], tetrahedral
Correct Answer: C
Solution :
\[BeC{{l}_{2}}\] has only two bond pair of electrons. So, its hybridisation is sp and bond angle is \[{{180}^{o}}\]. Its geometry is lineal. In \[BC{{l}_{3}}\], there is three bond pairs of electrons. So, its hybridisation is \[s{{p}^{2}}\] and bond angle is \[{{120}^{o}}\]. Its geometry is trigonal planar.
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