A) \[19.2\times {{10}^{-17}}N\]
B) \[1.92\times {{10}^{-17}}N\]
C) 0.192 N
D) None of these
Correct Answer: B
Solution :
Maximum magnetic field is given by \[{{B}_{0}}=\frac{{{E}_{0}}}{c}\] Here, \[{{E}_{0}}=600\,V{{m}^{-1}}\], \[c=3\times {{10}^{8}}m/s\], \[\therefore \] \[{{B}_{0}}=\frac{600}{3\times {{10}^{8}}}\] \[=2\times {{10}^{-6}}T\] Maximum magnetic force imposed on given charge is \[{{F}_{m}}=qv{{B}_{0}}=2ev{{B}_{0}}\] \[=2\times 1.6\times {{10}^{-19}}\times 3\times {{10}^{7}}\times 2\times {{10}^{-6}}\] \[=1.92\times {{10}^{-17}}N\]
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