BCECE Medical BCECE Medical Solved Papers-2008

  • question_answer
    An engine pumps up 100 kg of water through a height of 10 m in 5s. Given that the efficiency of engine is 60%. If \[g=10\,m{{s}^{-2}}\], the power of the engine is

    A)  3.3 kW       

    B)  0.33 kW

    C)  0.033 kW     

    D)  33 kW

    Correct Answer: A

    Solution :

    Key Idea Power is the rate at which a force does work. Efficiency of engine, \[\eta =60%\] Thus, power \[=\frac{work/times}{\eta }=\frac{100}{60}\times \frac{mgh}{l}\] Given, \[m=100\,kg,\,h=10\,m,\,\,t=5\,s\] and\[g=10\,\,m{{s}^{-2}}\]. Hence, power \[\frac{100}{60}\times \frac{100\times 10\times 10}{5}\]                 \[=3.3\times {{10}^{3}}W\] = 3.3 kW


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