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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2008

  • question_answer
    Three blocks of masses 2 kg, 3 kg and 5 kg are connected to each other with light st ring and are then placed on a friction less surface as shown in the figure. The system is pulled by a force F = 10 N, then tension \[{{T}_{1}}=\]

    A)  1 N            

    B)  5 N

    C)  8N             

    D)  ION

    Correct Answer: C

    Solution :

    Total mass of the system, \[M={{m}_{1}}+{{m}_{2}}+{{m}_{3}}\] = 2 + 3 + 5 = 10kg Force, F = 10 N Hence, acceleration, \[a=\frac{F}{M}=1\,m{{s}^{-2}}\] Now, tension Ti can be calculated as, \[{{T}_{1}}=({{m}_{2}}+{{m}_{3}})a=8\times 1=8\,N\]


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