A) 1014 m
B) 1414 m
C) 2828 m
D) none of these
Correct Answer: B
Solution :
The speed of sound (longitudinal waves) in water is given by \[v=\sqrt{\frac{B}{d}}\] where B is bulk modulus of water and d is density. Given, \[B=2\times {{10}^{9}}N/{{m}^{2}},d={{10}^{3}}kg//{{m}^{3}}\] \[\therefore \] \[v=\sqrt{\frac{2\times {{10}^{9}}}{{{10}^{3}}}}=1.141\times {{10}^{3}}\] \[1414\,m/s\] When sound travels back to the observer, it covers twice the distance. So, time of echo. \[t=\frac{2\,d}{v}\] \[\therefore \] \[d=\frac{tv}{2}=\frac{1414\times 2}{2}=1414\,m\]
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