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BCECE Medical BCECE Medical Solved Papers-2006

  • question_answer
    For \[CaC{{O}_{3}}(s)CaO(s)+C{{O}_{2}}(g)\] at\[{{927}^{o}}C\], \[\Delta H=176\,kJ\,mol\]; then \[\Delta E\] is :

    A)  180 kJ         

    B)  186.4 kJ

    C)  166.0 kJ       

    D)  160 kJ

    Correct Answer: C

    Solution :

    \[CaC{{O}_{3}}(g)CaO(s)+C{{O}_{2}}(g)\]                 \[(\Delta {{n}_{g}}=1-0=1)\] We know that,                 \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\]       \[176=\Delta E+1\times 8.31\times {{10}^{-3}}\times (273+927)\] \[\therefore \]  \[\Delta e=176-8.31\times {{10}^{-3}}\times 1200\] \[=176-9.97=166.03\,kJ\]


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