A) T
B) \[T-\frac{m{{v}^{2}}}{l}\]
C) \[T+\frac{m{{v}^{2}}}{l}\]
D) zero where T is the tension in the string.
Correct Answer: A
Solution :
When particle moves a circle, then the resultant force must act towards the centre and its magnitude F must satisfy \[F=\frac{m{{v}^{2}}}{l}\] This resultant force is directed towards the centre and it is called centripetal force. This force originates from tension T. \[\therefore \] \[F=\frac{m{{v}^{2}}}{l}=T\]
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