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BCECE Medical BCECE Medical Solved Papers-2006

  • question_answer
    A cart is moving horizontally along a straight line with constant speed 30 m/s. A projectile is to be fired from the moving cart in such a way that it will return to the cart after the cart has moved 80 m. At what speed (relative to the cart) must the projectile be fired? (Take \[g=10\,\,m/{{s}^{2}}\])

    A)  10 m/s        

    B)  \[10\sqrt{8}\] m/s

    C)  \[\frac{40}{3}\]m/s        

    D)  None of these

    Correct Answer: C

    Solution :

    As seen from the cart the projectile moves vertically upwards and comes back. The time taken by cart to cover 80 m                 \[=\frac{s}{v}=\frac{80}{30}=\frac{8}{3}\,s\] Here,     \[u=?,\,\,v=0,\,\,a=-g=10\,\,m/{{s}^{2}}\] (for a projectile going upwards) and        \[t=\frac{8/3}{2}=\frac{4}{3}\,s\] From first equation of motion                 \[v=u+at\]                 \[0=u-10\times \frac{4}{3}\] \[u=\frac{40}{3}\,m/s\]


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