A) Acetone
B) Propanal
C) Ethanal
D) Butanal
Correct Answer: A
Solution :
Key Idea: Fehling solution is cupric ion complex with tartarate onion. Aldehydes reduce it to red precipitate. The red precipitate is chemically Cu p \[\underset{\begin{smallmatrix} acetone \\ (a) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\,\,\,\,\,\,\underset{\begin{smallmatrix} propanal \\ (b) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,\] \[\underset{\begin{smallmatrix} ethanal \\ (c) \end{smallmatrix}}{\mathop{C{{H}_{3}}COH}}\,\] \[\underset{\begin{smallmatrix} butanal \\ (d) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO}}\,\] \[\therefore \] Only acetone which is ketone not an aldehyde does not give iodoform test.
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