A) Propene
B) 1-butene
C) 2-butene
D) 2-pentene
Correct Answer: C
Solution :
Key Idea: Anti Markownikoffs addition is shown when unsymmetrical reagent reacts with unsymmetrical double or triple bond containing compound. \[\underset{\begin{smallmatrix} (a) \\ propene \end{smallmatrix}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,\,\,\,\,\,\underset{\begin{smallmatrix} butene-1 \\ (b) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}-CH=C{{H}_{2}}}}\,\] \[\underset{\begin{smallmatrix} butene-2 \\ (a) \end{smallmatrix}}{\mathop{C{{H}_{3}}-CH=CH-C{{H}_{3}}}}\,\] \[\underset{propene-2}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH=CH-C{{H}_{3}}}}\,\] \[\because \] Choice [c] butene-2 is symmetrical alkene \[\therefore \] It does not show Anti Markownikoff addition.
You need to login to perform this action.
You will be redirected in
3 sec
