A) half of the potential energy
B) twice of the potential energy
C) one fourth of the potential energy
D) none of the above
Correct Answer: A
Solution :
Key Idea : Kinetic energy in an orbit \[=\frac{Z{{e}^{2}}}{8\,\,\pi \,{{E}^{o}}r}\] ? (i) Potential energy in an orbit \[=\frac{Z{{e}^{2}}}{4\,\,\pi \,{{E}^{o}}r}\] ... (ii) Comparing Eqs. (1) and (2). \[KE=\frac{1}{2}PE\]
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