BCECE Medical BCECE Medical Solved Papers-2004

  • question_answer
    A ball is thrown from a point with a speed \[{{v}_{0}}\]at an angle of projection \[\theta \]. From the same point and at the same instant, a person starts running with a constant speed \[\frac{{{v}_{0}}}{2}\] to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection?

    A)  Yes,\[{{60}^{o}}\]

    B)  Yes, \[{{30}^{o}}\]

    C)  No            

    D)  Yes, \[{{45}^{o}}\]

    Correct Answer: A

    Solution :

    Key Idea: Man will catch the ball if the horizontal component of velocity becomes equal to the constant speed of man. Horizontal velocity component of ball                 = constant speed of man i.e.,        \[{{v}_{0}}\cos \theta =\frac{{{v}_{0}}}{2}\] \[\Rightarrow \] \[\cos \theta =\frac{1}{2}\] \[\Rightarrow \] \[\cos \theta =\cos {{60}^{o}}\] \[\therefore \] \[\theta ={{60}^{o}}\]


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