A) 0.05 m/s
B) 0.5 m/s
C) 0.1 m/s
D) 0.2 m/s
Correct Answer: D
Solution :
Key Idea: In absence of any external force, linear momentum of a system is conserved. Linear momentum of bullet-gun system is conserved. i.e, Initial momentum = Final momentum \[\therefore \] \[0={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] or \[0=0.1\times 100+50\times {{v}_{2}}\] \[\therefore \] \[{{v}_{2}}=-\frac{10}{50}=-0.2\,\,m/s\] Negative sign implies recoil. Hence, the velocity of recoil is 0.2 m/s.
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