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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    Enthalpy change when 1g water is frozen at\[{{0}^{o}}C\] is : (\[\Delta {{H}_{fus}}=1.435\] kcal \[mo{{l}^{-1}}\])

    A)  0.0797 kcal    

    B)  -0.0797 kcal

    C)  1.435 kcal     

    D)  -1.435 kcal

    Correct Answer: B

    Solution :

    Key Idea: Enthalpy change per gram water is calculated by dividing \[\Delta \,H\] by molecular mass of water. Given    \[\Delta H=1.4354\,\,kcal\,\,mo{{l}^{-1}}\] \[=-\frac{1.4354}{18}=-0.0797\,k\,cal\,{{g}^{-1}}\]


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