A) \[\sqrt{{{K}_{sp}}}\]
B) \[{{({{K}_{sp}})}^{1/3}}\]
C) \[{{({{K}_{sp}}/4)}^{1/3}}\]
D) \[{{(8{{K}_{sp}})}^{1/2}}\]
Correct Answer: C
Solution :
Let the solubility of \[m=\frac{100\times 5.2\times 6}{0.52\times 100}=60\] \[PbC{{l}_{2}}P{{b}^{2+}}+2C{{l}^{-}}\] \[x\,mol/L\] \[x\] \[2x\] \[{{K}_{sp}}=[P{{b}^{2+}}]\,{{[C{{l}^{-}}]}^{2}}\] or \[=(x)\times {{(2x)}^{2}}\] or \[=4{{x}^{3}}\] \[\therefore \] \[x\sqrt[3]{\frac{{{K}_{sp}}}{4}}={{\left( \frac{{{K}_{sp}}}{4} \right)}^{1/3}}\]
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