BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    The temperature of cold, hot junction of a thermocouple are \[{{0}^{o}}C\] and \[{{T}^{o}}C\] respectively. The thermo-emf produced is \[E=AT-\frac{1}{2}B{{T}^{2}}\]. If A = 16, B = 0.08, the temperature of inversion will be:

    A)  \[{{100}^{o}}C\]

    B)  \[{{300}^{o}}C\]

    C)  \[{{400}^{o}}C\]

    D)  \[{{500}^{o}}C\]

    Correct Answer: C

    Solution :

    Key Idea: At the temperature of inversion, the thermo emf is zero. Let temperature of cold junction be \[{{0}^{o}}C\] and that of hot junction be \[{{T}^{o}}C\]. The relation for thermo emf is given by \[E=AT-\frac{1}{2}B{{T}^{2}}\] Given, \[A=16,\,\,B=0.08\] \[\therefore \] \[E=16\,T-\frac{1}{2}\times 0.08\times {{T}^{2}}\] Since, at temperature of inversion emf is zero, we have \[0=16\,T-0.04{{T}^{2}}\] \[\Rightarrow \] \[T=\frac{16}{0.04}={{400}^{o}}C\]


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