A) \[\Delta {{i}_{C}}=245\,\mu A,\,\Delta {{i}_{E}}=250\,\mu A\]
B) \[\Delta {{i}_{C}}=252\,\mu A,\,\Delta {{i}_{E}}=145\,\mu A\]
C) \[\Delta {{i}_{C}}=125\,\mu A,\,\Delta {{i}_{E}}=250\,\mu A\]
D) \[\Delta {{i}_{C}}=252\,\mu A,\,\Delta {{i}_{E}}=230\,\mu A\]
Correct Answer: A
Solution :
Current gain in common emitter mode of transistor \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] or \[\Delta {{i}_{C}}=\beta \,\Delta {{i}_{B}}\] Given, \[\beta =49,\,\,\Delta {{i}_{B}}=5.0\,\mu A\] \[\therefore \] \[\Delta {{i}_{C}}=49\times 5.0=245\,\mu A\] For a transistor, emitter current is the sum of base current and collector current. i.e., \[{{i}_{E}}={{i}_{C}}+{{i}_{B}}\] \[\Rightarrow \] \[\Delta {{i}_{E}}=\Delta {{i}_{C}}=\Delta {{i}_{B}}\] \[\therefore \] \[\Delta {{i}_{E}}=245+5.0=250\,\,\mu A\]
You need to login to perform this action.
You will be redirected in
3 sec
