BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    The wavelength of maximum energy, released during an atomic explosion was \[2.9\times {{10}^{-10}}m\]. Given that the Wiens constant is \[2.93\times {{10}^{-10}}m\], the maximum temperature attained must be of the order of:

    A)  \[{{10}^{-7}}K\]

    B)  \[{{10}^{7}}K\]

    C)  \[{{10}^{-3}}K\]

    D)  \[5.86\times {{10}^{-7}}K\]

    Correct Answer: B

    Solution :

    Wiens displacement law is given by \[{{\lambda }_{m}}T=\] constant (say b) Given, \[b=\] Wiens constant \[=2.93\times {{10}^{-3}}m-K\] \[{{\lambda }_{m}}=2.93\times {{10}^{-10}}m\] Substituting the values, we obtain \[T=\frac{b}{{{\lambda }_{m}}}\] \[=\frac{2.93\times {{10}^{-3}}}{2.93\times {{10}^{-10}}}\] \[={{10}^{7}}K\]


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