A) 4 rad/s
B) 16 rad/s
C) V21 rad/s
D) 2 rad/s
Correct Answer: A
Solution :
Key Idea: Tension in thread in vertical circular motion is maximum at the lowest point. At the lowest point of vertical circular motion \[{{T}_{\max }}=mg+\frac{m{{v}^{2}}}{r}\] or \[{{T}_{\max }}=mg+mr{{\omega }^{2}}\] ... (i) Given, \[{{T}_{\max }}=3.7\times 10=37\,N\] \[mg=0.5\times 10=5\,N\] Thus, Eq. (i), becomes \[37=5+0.5\times 4\times {{\omega }^{2}}\] or \[{{\omega }^{2}}=\frac{37-5}{0.5\times 4}=\frac{32}{2}=16\] or \[\omega =4\] rad/s
You need to login to perform this action.
You will be redirected in
3 sec
