BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    When two conductors of charges and potentials \[{{C}_{1}},\,\,{{V}_{1}}\] and \[{{C}_{2}},\,\,{{V}_{2}}\] respectively are joined, the common potential will be :

    A)  \[\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}\]

    B)  \[\frac{{{C}_{1}}V_{1}^{2}+{{C}_{2}}V_{2}^{2}}{V_{1}^{2}+V_{2}^{2}}\]

    C)  \[{{C}_{1}}+{{C}_{2}}\]

    D)  \[\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]

    Correct Answer: D

    Solution :

    When two conductors of capacities \[{{C}_{1}}\] and \[{{C}_{2}}\]and potentials \[{{V}_{1}}\] and \[{{V}_{2}}\] are connected by a conducting wire, charge redistributes in these conductors till potential of both the conductors become equal, known as common potential. Common potential \[=\frac{net\text{ }charge}{total\text{ }capacity}\] i.e., \[V=\frac{{{q}_{1}}+{{q}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] or \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]


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