A) \[5g\,N{{H}_{3}}\]
B) \[11\,g\,C{{O}_{2}}\]
C) \[8\,g\,S{{O}_{2}}\]
D) \[4\,g\,{{H}_{2}}\]
Correct Answer: D
Solution :
Key Idea: Molecular mass in gram = 1 mole \[=6.023\times {{10}^{23}}\] molecules, find the moles of all given choices. More the moles, more will be number of molecules in it. [a] 5 g of \[N{{H}_{3}}\] (M. wt. of \[N{{H}_{3}}=17\]) 17 g of \[N{{H}_{3}}=1\] mol \[\therefore \] 5 g of \[N{{H}_{3}}=\frac{1}{17}\times 5=0.294\,mol\] [b] 11 g of \[C{{O}_{2}}\] (M. wt. of \[C{{O}_{2}}=44\,g\]) 44 g of \[C{{O}_{2}}=1\] mol \[\therefore \] 11 g of \[C{{O}_{2}}=\frac{1}{44}\times 11=0.25\,\,mol\] [c] 8 g of \[S{{O}_{2}}\] (M. wt. of \[S{{O}_{2}}=64\]) 64 g of \[S{{O}_{2}}=1\,\,mol\] \[\therefore \] 8 g of \[S{{O}_{2}}=\frac{1}{64}\times 8=0.125\,\,mol\] [d] 4 g of \[{{H}_{2}}\] (M. wt. of \[{{H}_{2}}=2\]) 2 g of \[{{H}_{2}}=1\,\,mol\] \[\therefore \] 4 g of \[{{H}_{2}}=\frac{1}{2}\times 4=2\,\,mol\] \[\therefore \] 4 g of \[{{H}_{2}}\] has highest moles.
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