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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    If heat of neutralisation of \[C{{H}_{3}}COOH\] and \[NaOH\] is -50.6 kJ equivalent and the heat of neutralisation of \[N{{H}_{4}}OH\] and \[HCl\] is -51.4 kJ equivalent then the heat of neutralisation of \[C{{H}_{3}}COOH\] and \[N{{H}_{4}}OH\] is:

    A)  102 kJ       

    B)  -0.8 kJ

    C)  0.8 kJ        

    D)  none of these

    Correct Answer: D

    Solution :

    Key Idea: Heat of neutralization of strong acid by strong base is constant. But for weak acid or weak base it is less than constant value because some heat is required to dissociate weak acid or weak base. 1. \[C{{H}_{3}}COOH\] is weak acid. 2. \[N{{H}_{4}}OH\] is weak base. Heat of neutralization of \[C{{H}_{3}}COOH+N{{H}_{4}}OH\] cannot be calculated without the data about dissociation constant of \[C{{H}_{3}}COOH\] and \[N{{H}_{4}}OH\].


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