BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    Find the temperature of hydrogen gas which has the same velocity as that of oxygen at a temperature of \[{{0}^{o}}C\]:

    A)  \[273\div 16\text{ }K\]     

    B)  \[273\times 8\text{ }K\]

    C)  \[273\div 32\text{ }K\]     

    D)  \[273\times 4\text{ }K\]

    Correct Answer: A

    Solution :

    Key Idea: \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\] For \[{{O}_{2}}\] \[T=273\,K,\,M=32\] \[\therefore \] \[{{v}_{rms}}({{O}_{2}})=\sqrt{\frac{3R\times 273}{32}}\] ?. (i) For \[{{H}_{2}}\] \[T=?\,\,M=2\]                 \[{{v}_{rms}}{{H}_{2}}=\sqrt{\frac{3R\times T}{2}}\] Given    \[{{v}_{rms}}{{O}_{2}}={{v}_{rms}}\,\,{{H}_{2}}\] \[\therefore \] \[\sqrt{\frac{3R\times 273}{32}}=\sqrt{\frac{3R\times T}{2}}\] or            \[\frac{273}{32}=\frac{T}{2}\] \[\therefore \] \[T=\frac{273\times 2}{32}=\frac{273}{16}K\]


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