BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    A stone is thrown with an initial speed of 4.9 m/s from a bridge in vertically upward direction. It falls down in water after 2 s. The height of the bridge is :

    A)  24.7 m         

    B)  19.8 m

    C)  9.8m          

    D)  4.9m

    Correct Answer: C

    Solution :

    From Newtons second equation of motion, we have                 \[s=ut+\frac{1}{2}g{{t}^{2}}\] where u is initial velocity, t is time, s is displacement, and g is the acceleration due to gravity. Since, gravity attract every body towards its centre, downward direction is taken as positive and upward negative. Hence,  \[s=ut+\frac{1}{2}g{{t}^{2}}\]                 \[=(-4.9\times 2)+\frac{1}{2}\times 9.8\times {{2}^{2}}\] \[=9.8+19.6=9.8\,\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner