A) 1
B) 4
C) \[\frac{1}{4}\]
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
Key Idea, \[{{K}_{c}}=\frac{[C]\,\,[D]}{[A]\,\,[B]}\] where \[{{K}_{c}}=\] equilibrium constant. \[A+BC+D\] Initial moles 4 4 0 0 Moles after (4 - 2) (4 - 2) 2 2 reaction . = 2 = 2 Let volume of container = V L \[\therefore \] \[{{K}_{c}}=\frac{(2/V)\times (2/V)}{(2/V)\times 2/V}\]
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