A) 5
B) 4
C) 6
D) 3
Correct Answer: D
Solution :
Key Idea: Draw all isomers and count them saturated pentane is \[{{C}_{5}}{{H}_{12}}\]. (i) \[C{{H}_{3}}-C{{H}_{2}}\underset{pentane}{\mathop{-C{{H}_{2}}-C{{H}_{2}}}}\,-C{{H}_{3}}\] (ii) \[\underset{2-methyl\text{ }butane}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{3}}}}\,\] (iii) \[\underset{2,2-dimethyl\text{ }propane}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\] \[\therefore \] Total number of 3 isomers are possible by\[{{C}_{5}}{{H}_{12}}\] (saturated pentane).
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