BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    The work done to form a layer of soap solution of size \[10\times 10\,cm\] will be : (surface tension of soap solution is \[3\times {{10}^{-2}}N/m\])

    A)  \[6\times {{10}^{-2}}J\]

    B)  \[6\times {{10}^{-4}}J\]

    C)  \[3\times {{10}^{-2}}J\]

    D)  \[3\times {{10}^{-4}}J\]

    Correct Answer: B

    Solution :

    Key Idea : Surface tension T can be defined as the work done informing the soap film of unit surface area. Surface tension of a soap film is written as                 \[T=\frac{work\text{ }done}{area}\] or            Work done = T \[\times \]area Here, area \[=2\times 10\times 10\,c{{m}^{2}}=2\times {{10}^{-2}}{{m}^{2}}\],                 \[T=3\times {{10}^{-2}}N/m\]                 Hence, work done \[=3\times {{10}^{-2}}\times 2\times {{10}^{-2}}\] \[=6\times {{10}^{-4}}J\]


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