BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    At 300 K, the ratio of the average molecular kinetic energy of \[U{{F}_{6}}\] to that of \[{{H}_{2}}\] is :

    A)  2 : 7        

    B)  7 : 2

    C)  6 : 2        

    D)  1 : 1

    Correct Answer: D

    Solution :

    Key Idea: Average molecular kinetic energy \[=\frac{3}{2}\,kT\] Given, T = 300 K for both \[U{{F}_{2}}\] and \[{{H}_{2}}\]. \[\therefore \] Average molecular kinetic energy does not depend on molecular mass of substance. Average molecular kinetic energy of \[{{H}_{2}}\] \[=\frac{3}{2}k\times 300\] ... (i) Average molecular kinetic energy of UI^                 \[=\frac{3}{2}k\times 300\] ... (ii) Dividing Eq. (i) by Eq. (ii) we get 1:1


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