A) 1-propanol
B) methanol
C) 2-butanol
D) 1-butanol
Correct Answer: C
Solution :
Key Idea: It, is used to detect presence of\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-\] group and \[C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{\underset{|}{\mathop{C}}\,}}\,-H\] group. The compounds having these groups give yellow ppt. of iodoform when \[{{I}_{2}}\] and aq. NaOH is added. [a] \[\underset{1-propanol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] [b] \[\underset{methanol}{\mathop{C{{H}_{3}}OH}}\,\] [c] \[\underset{2-butanol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{2}}C{{H}_{3}}}}\,\] [d] \[\underset{1-butanol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] \[\therefore \] Only 2-butanol gives iodoform test.
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