BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    A monoatomic gas \[(\gamma =5/3)\] at pressure P is suddenly compressed to \[\frac{1}{8}\]th of its volume adiabatically, the pressure of gas is :

    A)  \[\frac{43}{3}P\]          

    B)  8 P

    C)  32 P

    D)  \[\frac{24}{5}P\]

    Correct Answer: C

    Solution :

    The condition that must be obeyed by an ideal gas in an adiabatic process is given by                 \[P{{V}^{\gamma }}=\] constant or            \[{{p}_{1}}{{V}_{1}}^{\gamma }={{p}_{2}}{{V}_{2}}^{\gamma }\] or            \[{{p}_{2}}={{p}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\] Here,     \[{{p}_{1}}=p,\,\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{1}{8},\,\,\gamma =\frac{5}{3}\]                 \[\therefore \] \[{{p}_{2}}=p\,\,{{(8)}^{5/3}}\]                 or \[{{p}_{2}}=p\,\,{{({{2}^{3}})}^{5/3}}=32\,p\] Note: The equation PV^ = constant can be written in terms of other pair of thermodynarnic variables by combining it with the ideal gas law \[(PV=nRT)\]. In doing so, we will find that, \[T{{V}^{\gamma -1}}=\] constant and \[{{T}^{\gamma }}\,{{P}^{1-\gamma }}=\] constant.


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