A) \[100\,mL\,of0.1\text{ }M\,AgN{{O}_{3}}\text{ }+\text{ }100\,mL\,of0.1\text{ }M\,Kl\]
B) \[100\,mL\,of0.1\text{ }M\,AgN{{O}_{3}}+100\,mL\,of0.2\text{ m}\,Kl\]
C) \[100\,mL\,of0.2\text{ }M\,AgN{{O}_{3}}+100\,mL\,of0.1\text{ M}\,Kl\]
D) \[100\,mL\,of0.15\text{ }M\,AgN{{O}_{3}}+100\,mL\,of0.15\text{ M}\,Kl\]
Correct Answer: B
Solution :
Negatively charged colloidal sol is formed when \[\text{AgN}{{\text{O}}_{\text{3}}}\]is completely precipitated as Agl and extra Kl is absorbed on Agl \[A{{g}^{+}}+{{l}^{-}}\xrightarrow{{}}Agl\] \[Agl+{{l}^{-}}\xrightarrow{{}}{{[Agl]}^{-}}\] Thus, \[[A{{g}^{+}}]<[{{l}^{-}}]\]
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