A) 50%
B) 11.5%
C) 4.01%
D) 1.19%
Correct Answer: B
Solution :
Theoretical value of dipole moment of 100% ionic character\[=e\times d\] \[=(1.6\,\times \,{{10}^{-19}}C)(1.41\times {{10}^{-10}}m)\] \[=2.26\times {{10}^{-29}}\,Cm\] Observed value of dipole moment \[=2.60\times {{10}^{-30}}Cm\] \[\therefore \] Percent ionic character \[\text{=}\frac{\text{observed}\,\text{value}}{\text{theoretical}\,\text{value}}\text{ }\!\!\times\!\!\text{ 100}\] \[\text{=}\frac{2.60\times {{10}^{-30}}}{2.26\times {{10}^{-29}}}\times 100\] \[=11.5%\]
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