BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    Arrange the following in the order of rate of oxidation with periodic acid
    (i)\[HOC{{H}_{2}}C{{H}_{2}}OH,\]
    (ii) \[C{{H}_{3}}CHOHCHOHC{{H}_{3}}\]
    (iii) \[{{(C{{H}_{3}})}_{2}}COHCOH{{(C{{H}_{3}})}_{2}}\]

    A) I > II > III

    B)              II > I > III              

    C)        III > II > I              

    D)   I > III = II

    Correct Answer: A

    Solution :

    Rate of oxidation depends upon steric hinderance. Greater the steric hinderance the slower is the oxidation. Thus, the correct order is \[\underset{(i)}{\mathop{\underset{C{{H}_{2}}OH}{\mathop{\underset{|}{\mathop{C{{H}_{2}}OH}}\,}}\,>\,}}\,\,\,\,\underset{(ii)}{\mathop{\underset{C{{H}_{3}}CHOH}{\mathop{\,\underset{|}{\mathop{C{{H}_{3}}CHOH}}\,}}\,}}\,>\,\underset{(iii)}{\mathop{\underset{{{(C{{H}_{3}})}_{2}}COH}{\mathop{\underset{|}{\mathop{\,\,\,{{(C{{H}_{3}})}_{2}}COH}}\,}}\,}}\,\]


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