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BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    The internal resistance of a cell of emf 2 V is \[0.1\,\pi .\]If it is connected to a resistance of \[3.9\pi ,\] then the voltage across the cell will be (in volts)

    A)  2 V                                        

    B)         0.5 V                    

    C)         1.95 V                  

    D)         2.5 V

    Correct Answer: C

    Solution :

    We know \[r=\left( \frac{E}{V}-1 \right)R\] hence,   \[R=3.9\pi ,\,\,E=2.0\,V,\,r=0.1\,\Omega \] hence,  \[V=\text{ }1.95\text{ }V\]


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