A) \[245\pi \]as shunt
B) \[2450\pi \]as series
C) \[2500\pi \]as shunt
D) \[2550\pi \]in series
Correct Answer: B
Solution :
Given \[{{R}_{g}}=50\,\Omega ,\] \[{{l}_{g}}=25\times 4\times {{10}^{-4}}A\] \[={{10}^{-2}}A\] Range of V = 25 volts Resistance, \[R=\frac{V}{{{l}_{g}}}-{{R}_{g}}\] \[=\left( \frac{25}{{{10}^{-2}}}-50 \right)\Omega \] \[=2450\,\Omega \] Thus, a resistance of \[2450\,\Omega \]is connected is series to convert it into a voltmeter.
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