A) 4.3 cm
B) 4.5 cm
C) 5 cm
D) 7 cm
Correct Answer: B
Solution :
Total volume is conserved \[\therefore \] \[\frac{4\pi }{3}{{(3)}^{3}}+\frac{4\pi }{3}{{(4)}^{3}}=\frac{4\pi }{3}{{R}^{3}}\] or \[R\cong 4.5\,cm\]
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