BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
     Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220V AC supply line, the power drawn by the combination in each case respectively will be

    A) \[50,200W\]     

    B)       \[~50W,20W\text{ }\]   

    C)        \[100\text{ }W,50\text{ }W\]   

    D)        \[~200\text{ }W,150\text{ }W\]

    Correct Answer: A

    Solution :

    In series, power, \[P=\frac{{{V}^{2}}}{2R}=\frac{P}{2}=50\,W\] In parallel, power, \[P=\frac{{{V}^{2}}}{{\scriptstyle{}^{R}/{}_{2}}}=2P=20\,W\]


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