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BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    The slope of tangent to the  curve \[x={{t}^{2}}+3t-8,y=2{{t}^{2}}-2t-5\]at the point \[(2,-1)\]is

    A)  \[\frac{22}{7}\]                               

    B)         \[\frac{6}{7}\]                  

    C)         \[-6\]                                   

    D)         None of these

    Correct Answer: B

    Solution :

    \[t=2\]for the point \[(2,-1)\] \[\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}=\frac{4t-2}{2t+3}=\frac{6}{7}\]for \[t=2\]


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