A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[{{\tan }^{-1}}\left| \frac{12}{5} \right|\]
D) \[{{\tan }^{-1}}\left| \frac{7}{3} \right|\]
Correct Answer: D
Solution :
Here, \[a=2,h=\frac{3}{2},b=-5\] \[\therefore \] \[\tan \theta =\left| \frac{2\sqrt{{{\left( \frac{3}{2} \right)}^{2}}+10}}{2-5} \right|=\left| \frac{\sqrt{49}}{-3} \right|\] \[\Rightarrow \] \[\theta ={{\tan }^{-1}}\left| \frac{7}{3} \right|\]
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