BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    The equation \[\sqrt{3}\sin x+\cos x=4\]has

    A)  infinitely many solutions

    B)         no solution

    C)         two solutions

    D)         only one solution

    Correct Answer: B

    Solution :

    We know that, \[-\sqrt{{{a}^{2}}+{{b}^{2}}}\le a\cos \theta +b\sin \theta \le \sqrt{{{a}^{2}}+{{b}^{2}}}\] \[\therefore \]\[-\sqrt{3+1}\le \sqrt{3}\sin x+\cos x\le \sqrt{3+1}\] \[\Rightarrow \]\[-2\le \sqrt{3}\sin x+\cos x\le \sqrt{2}\] But \[\sqrt{3}\sin x+\cos x=4.\] Hence, given equation has no solution.


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