A) \[C{{H}_{3}}-\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-C{{H}_{2}}I\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-\underset{Cl}{\overset{I}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H\]
C) \[C{{H}_{3}}-C{{H}_{2}}\overset{I}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}Cl\]
D) \[C{{H}_{3}}C{{H}_{2}}-\underset{Cl}{\overset{I}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH+HCl\xrightarrow{{}}\] \[C{{H}_{3}}C{{H}_{2}}-\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\xrightarrow{HI}\] \[\underset{2-\text{chloro}-2-\text{iodobutane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{Cl}{\overset{I}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\]
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