A) NO
B) \[N_{2}^{+}\]
C) CO
D) \[{{O}_{2}}\]
Correct Answer: C
Solution :
Paramagnetic character is shown by those atoms or molecules which have unpaired electrons. In the given molecules CO is not paramagnetic, since, it does not have unpaired electrons. The configuration of CO molecule is \[CO(14)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\pi 2p_{x}^{2}\]\[\approx \pi 2p_{y}^{2},\sigma 2p_{z}^{2}\]
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