BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be

    A)  \[\frac{2{{\varepsilon }_{0}}A}{d}\]       

    B)         \[\frac{{{\varepsilon }_{0}}A}{d}\]

    C)  \[\frac{3{{\varepsilon }_{0}}A}{d}\]       

    D)         \[\frac{3{{\varepsilon }_{0}}A}{2d}\]

    Correct Answer: C

    Solution :

    The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence, equivalent capacitance  \[=3C=\frac{3{{\varepsilon }_{0}}A}{d}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner