A) \[0.137\text{ }s\]
B) \[0.328\text{ }s\]
C) \[0.628s\]
D) \[1.000\,s\]
Correct Answer: C
Solution :
The force constant of the spring, \[k=\frac{F}{x}=\frac{0.5\times 10}{0.2}=25\,N/m\] Now, if the mass of 0.25 kg is suspended by the spring, then the period of oscillation, \[T=2\pi \sqrt{\frac{m}{k}}\] \[=2\pi \sqrt{\frac{0.25}{25}}=0.628\,s\]
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