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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    If \[4{{\sin }^{-1}}x+{{\cos }^{-1}}x=\pi ,\] then the value of \[x\]is

    A)  0                                            

    B)         \[1/2\]                  

    C)         1                                            

    D)         \[-\text{ }1\]

    Correct Answer: B

    Solution :

    From the given relation, we have \[3{{\sin }^{-1}}x+{{\sin }^{-1}}x+{{\cos }^{-1}}x=\pi \] \[\Rightarrow \]    \[3{{\sin }^{-1}}x+\frac{\pi }{2}=\pi \Rightarrow 3{{\sin }^{-1}}x=\pi /2\] \[\Rightarrow \]    \[{{\sin }^{-1}}x=\pi /6\Rightarrow x=1/2\]


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