2. Solved Papers
  3. BCECE Engineering

BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    If \[x\,\text{mol}\,{{\text{L}}^{-1}}\]is the solubility of \[\text{KAl(S}{{\text{O}}_{\text{4}}}{{\text{)}}_{\text{2}}}\] then \[{{\text{K}}_{\text{sp}}}\]is equal to

    A) \[{{x}^{3}}\]                      

    B)         \[4{{x}^{4}}\]                   

    C)  \[{{x}^{4}}\]                     

    D)         \[4{{x}^{3}}\]

    Correct Answer: B

    Solution :

    \[KAl{{(S{{O}_{4}})}_{2}}\xrightarrow{{}}\underset{x}{\mathop{{{K}^{+}}}}\,+\underset{x}{\mathop{A{{l}^{3+}}}}\,+\underset{2x}{\mathop{2SO_{4}^{2-}}}\,\] \[{{K}_{sp}}=[{{K}^{+}}][A{{l}^{3+}}]{{[SO_{4}^{2-}]}^{2}}\] \[=(x)(x){{(2x)}^{2}}=4{{x}^{4}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner