BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    Given, C (diamond)\[+\,{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\Delta H =-395\,kJ\] C (graphite) \[+\,{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\Delta H =-393\,kJ\] The heat of formation of diamond from graphite is

    A) \[+\,2.0\,kJ\]                    

    B) \[-1.5\,kJ\]        

    C) \[-788\,kJ\]       

    D) \[788\,kJ\]

    Correct Answer: A

    Solution :

    \[C(dimond)+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\,\,\,\Delta H =-395\,kJ\] ?(i) \[C(graphite)+{{O}_{2}}\xrightarrow{\,}C{{O}_{2}};\,\Delta H=-393\,kJ\] ?(ii) Eq. (i) - Eq. (ii), we get \[C(diamond)\xrightarrow{{}}C(graphite)\] \[\Delta H=[-395-(-393)]\,kJ=-2.0\,kJ\] and \[C(graphite)\xrightarrow{{}}C(diamond);\] \[\Delta H=+2.0\,kJ\]


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